From mint-bounce@lists.fishpool.fi Mon Nov 3 12:48:10 2008 Date: Mon, 3 Nov 2008 18:43:26 +0100 (CET) From: Frank Naumann X-X-Sender: fnaumann@localhost.localdomain To: Jo Even Skarstein Cc: mint@fishpool.com Subject: Re: [MiNT] (fwd) Revisited: HDDRIVER, FAT32, MiNT, FAT too small In-Reply-To: <200811021055.mA2Atngt029398@tyrell.nvg.ntnu.no> Message-ID: References: <200811021055.mA2Atngt029398@tyrell.nvg.ntnu.no> User-Agent: Alpine 2.00 (LFD 1167 2008-08-23) MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII; format=flowed X-Virus-Scanned: by amavisd-new at relay.boerde.de X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on relay.boerde.de X-Spam-Status: No, hits=- tagged_above=-50.5 required=7.0 WHITELISTED X-Spam-Level: X-ecartis-version: Ecartis v1.0.0 Sender: mint-bounce@lists.fishpool.fi Errors-to: mint-bounce@lists.fishpool.fi X-original-sender: fnaumann@boerde.de Precedence: bulk List-help: List-unsubscribe: List-Id: X-List-ID: List-subscribe: List-owner: List-post: Hello Jo Even! > When creating a FAT32 partition of 4095 MB HDDRUTIL allocates 8386528 > sectors of 512 bytes for the FATs and the actual data area. 8174 sectors > are allocated for each FAT, which means that 8386528-2*8174=8370180 > sectors remain for the actual data. There are 8 sectors per cluster, > which means that there are 8386528/8=1046272 data clusters. For each of > these 1046272 clusters a 32 bit FAT entry is required, which means that > 1046272*4=4185088 bytes are needed per FAT. This is exactly what 8174 > sectors per FAT amount to: 8174*512=4185088. > > This calculation shows that the number of FAT sectors allocated by > HDDRUTIL is exactly the number of sectors needed. > If my calculation is right MiNT is wrong and should be fixed. If my > calculation is wrong please point out the error so that I can fix my code. What about the two empty (unused) entries at the start of each FAT table? Regards, Frank -- ATARI FALCON 060 // MILAN 060 ----------------------------- http://sparemint.org/ e-Mail: fnaumann@boerde.de